a 5.7 kg ball rolls over the edge of a 4.4 m tall cliff. If the total mechanical energy of the ball is 890 j at the instant that it goes over the edge, how fast is the ball moving?

Not sure how to get V when you know TME.

2 answers

The answer depends upon whether the ball is hollow inside, like a basketball or tennis ball, or solid and of uniform density.

Total kinetic energy is
(1/2)MV^2 + (1/2) I w^2
in either case

where w is the angular rotation rate, V/R, and I is the moment of inertia
That just confused me more cause it's just asking for Velocity and we haven't talked anything about w or i