Asked by James
a 5.7 kg ball rolls over the edge of a 4.4 m tall cliff. If the total mechanical energy of the ball is 890 j at the instant that it goes over the edge, how fast is the ball moving?
Not sure how to get V when you know TME.
Not sure how to get V when you know TME.
Answers
Answered by
drwls
The answer depends upon whether the ball is hollow inside, like a basketball or tennis ball, or solid and of uniform density.
Total kinetic energy is
(1/2)MV^2 + (1/2) I w^2
in either case
where w is the angular rotation rate, V/R, and I is the moment of inertia
Total kinetic energy is
(1/2)MV^2 + (1/2) I w^2
in either case
where w is the angular rotation rate, V/R, and I is the moment of inertia
Answered by
James
That just confused me more cause it's just asking for Velocity and we haven't talked anything about w or i
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