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A ball rolling with initial velocity of 40m/s(W) undergoes an acceleration of 5.0m/s^2(N) for a period of 6.0seconds.

(A) what is the final velocity of the ball?
(B) what is the displacement of the ball in the 6.0 sec

1 answer

vf=vi+at

d=vi*t + 1/2 a t^2

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