A ball of mass 8 kg is thrown vertically upward from the ground , with an initially velocity of 25 m/s. Determine the maximum height to which it will travel if atmospheric resistance is neglected.

Answer 1

h(t) = 25t - 4.9t^2 = t(25-4.9t)

max height is reached halfway between 0 and 25/4.9, at t=2.55

h(2.55) = 31.89

Answer 2

ΔKE= - ΔPE
KE2-KE1 =-(PE2 -PE1)
0 - m•v²/2 =0 – m•g•h.
h= v²/2g=25²/2•9.8 = 31.89 m

Answer 3

Please help me to elaborate the answer as i tried but couldn't

Answer 4

A ball of mass 8 kg is thrown vertically upward from the ground , with an initially velocity of 25 m/s. Determine the maximum height to which it will travel if atmospheric resistance is neglected