A ball of mass 200g, travelling with a velocity of 100m/s, collides with another ball of mass 800g, moving at 50m/s in thesame direction. If they stick togdther, what will be their common velocity?

Answer 1

conservation of momentum applies.
initial momentum=final momentum
200*100+800*50=(200+800)Vf solve for Vf, in m/s

Answer 2

A ball of mass 200g, travelling with a velocity of 100m/s, collides with another ball of mass 800g, moving at 50m/s in thesame direction. If they stick togdther, what will be their common velocity?

Answer 3

Using inelastic collision formula:
m1u1 +m2u2 = (m1+m2)V
(200*100) + (800*50) = ( 200+800)V
20000+40000 = 1000V
60000 = 1000V
V = 60000 / 1000
V = 60

Answer 4

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Answer 5

Ok

Answer 6

Momentum before impulse= momentum after impulse

(0.2×100)+(0.8×50)=(0.2+0.8)v
where v is the common velocity.
(20+40)=1v
60=v
v=60
therefore, the common velocity is 60m/s