Asked by somay
A ball of mass 100 g travelling with a velocity of 100 m/s collides with another ball of mass 400 g moving at 50 m/s in the same direction. If they stick together, calculate:
(i) their common velocity
(ii) loss of enery and hence state the type collision involved.
I had calculated their common velocity of which i got 60m/s.
Please help me (ii)
(i) their common velocity
(ii) loss of enery and hence state the type collision involved.
I had calculated their common velocity of which i got 60m/s.
Please help me (ii)
Answers
Answered by
AMELIA
linear momentum p=mv
lets say m1 =0.1 kg
m2=0.4kg
before collision pi=(m1. u1)+(m2 . u2)
pi=(0.1 . 100) + ( 0.4.50) = 30
when they collide together pf= (m1+m2)vf
since linear momentum is always conserved pi=pf
pf= (m1+m2)vf =pf
(0.1+0.4) vf = 30
vf=60m/s
you are correct
b)
when two objects stick together their collision is a PERFECTLY inelastic collision
you now have to calculate ki and kf
ki-kf=loss of energy
kf = 1/2 . (m1+m2). vf^2
kf = 1/2 . (0.1+0.4). 60^2=900j
ki = 1/2 .m1 . u1^2 + 1/2 m2 . u2^2
ki = (1/2 . 0.1. 100^2 ) + (1/2 . 0.4 . 50^2)=1000J
energy lost = 100 J
lets say m1 =0.1 kg
m2=0.4kg
before collision pi=(m1. u1)+(m2 . u2)
pi=(0.1 . 100) + ( 0.4.50) = 30
when they collide together pf= (m1+m2)vf
since linear momentum is always conserved pi=pf
pf= (m1+m2)vf =pf
(0.1+0.4) vf = 30
vf=60m/s
you are correct
b)
when two objects stick together their collision is a PERFECTLY inelastic collision
you now have to calculate ki and kf
ki-kf=loss of energy
kf = 1/2 . (m1+m2). vf^2
kf = 1/2 . (0.1+0.4). 60^2=900j
ki = 1/2 .m1 . u1^2 + 1/2 m2 . u2^2
ki = (1/2 . 0.1. 100^2 ) + (1/2 . 0.4 . 50^2)=1000J
energy lost = 100 J
Answered by
somay
wow! it's great! Thank you somuch AMELIA.
But please help me with the meaning of ki and kf
But please help me with the meaning of ki and kf
Answered by
AMELIA
ki is the kinetic energy initial how much energy is there in the system in the form a speed at the beggining of the collision as you know there are two forms of mechanical energy ( kinetic energy and potential ) when the object is moving it has kinetic energy but when it collides some of the kinetic energy transforms into heat and sound thus the speed of the object slows down.When we calculate the Kf we calculate the energy after the collision.Like I said during an Inelastic collision kf is less then ki because there has been lost of energy ( transform into heat and sounds etcc
Answered by
Dolapo
Meaning of pi and pf
Answered by
blessed John
Thanks
for the solving
for the solving
Answered by
Anonymous
SswPlease i dont really understand this answer
Answered by
Joy
I dont understand
Answered by
Idera
Thanks for that
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