a. V^2 = Vo^2 + 2g*h.
V^2 = 0 + 19.6*1 = 19.6, V = 4.43 m/s.
b. V^2 = Vo^2 + 2g*h.
0 = Vo^2 -19.6*0.35, Vo = 2.62 m/s.
c. M*V-M*Vo = 0.15*4.43 - 0.15*2.62 = 0.272Mass-m/s.
d. V = Vo + a*t.
-2.62 = 4.43 + a*0.06, a = -117.5 m/s^2.
F = M*a = 0.15 * 117.5 = 17.6 N.
A ball of mass 0.15kg is dropped from a height of 1.0m onto a flat surface and rebounds to a height of 0.35m.
Calculate:
(a) The speed of the ball just before the impact,
(b) The speed of the ball just after impact,
(c) The change of momentum,
(d) The force of impact, if the time of contact at the surface was 60ms.
2 answers
A uniform ladder of length 20.0m and weight 750 N is propped up against a smooth vertical wall with its lower end on a rough horizontal surface. The coefficient of friction between the ladder and this horizontal surface is 0.40.
(b) Work out and add the numerical values of each force clearly showing your justification in each case.
(c) Hence, calculate a value for the angle between the ladder and the wall if the ladder just remains in stable equilibrium.
Can you please help me on these questions. I have completed a but can't do b and c.
(b) Work out and add the numerical values of each force clearly showing your justification in each case.
(c) Hence, calculate a value for the angle between the ladder and the wall if the ladder just remains in stable equilibrium.
Can you please help me on these questions. I have completed a but can't do b and c.
0 answers