A ball of mass 0.15kg is dropped from rest at a height of 1.25m. it rebounds from the floor to reach a height of 0.960n. what impulse is given to the ball from the floor?

i don't have a clue where to start.
i know impulse is constant force x change in time or time elapsed, but i don't any time with this question any help?

5 answers

Impulse= change of momentum
Remember momentum is a vector, it was downward as the ball fell, and upward as it rebounded, so it changed sign

Impuls= finalmomentum- initialmomentum
=m(vf-vi)

Now one has to deal with the heights.
Using energy concepts to change between heights and velocities...
v^2=2gh so v= sqrt (2gh)

Impulse= m*sqrt[(2g)(.960+1.25)]
Notice carefully the sign in the last parenthesis, you need to understand why it is positive.

do you do high school physics

-0.09

Physics

0.24kgm/s