A ball is thrown with an initial velocity of 20mls at an angle of 30 to the horizontal calculate time of flight maximum height the horizontal range of the ball how do I know If you have done it

Answer 1

horizontal problem:
u = 20 cos 30 the whole time
d = u T
vertical problem:
Vi = 20sin 30 = 10
v = Vi - g t
at top v = 0
g t = 10
t = 10/9.81 or about one second to top
time of flight = 2t = about 2 seconds

h = Vi t - 4.9 t^2
= 10(1) - 4.9 = about 5 meters

Answer 2

Oh, range d = 20 cos 30 * 20
= 400 * .866