A ball is thrown with an initial velocity of 20mls at an angle of 30 to the horizontal calculate time of flight maximum height the horizontal range of the ball

Answer 1

Vo = 20m/s[30o].
Xo = 20*Cos30 = 17.32 m/s.
Yo = 20*sin30 = 10 m/s.

a. Y = Yo + g*Tr.
0 = 10 -9.8Tr, Tr = 1.02 s. = Rise time.
Tf = Tr = 1.02 s.
Tr+Tf = 1.02 + 1.02 = 2.04 s. = Time in flight.

b. h = Yo*Tr + 0.5g*Tr^2.
h = 10*1.02 - 4.9*1.02^2 =

c. Range = Xo*(Tr+Tf)= 17.32*2.04 =