A ball is thrown with a horizontal velocity of 2 m/s from a vertical height of 50 m above ground. neglect air resistance and determine:

Question

the horizontal displacement traveled by the ball. can someone please explain this to me!

Answer 1

One needs to find how long it is in the air, the initial height determines that.
h=1/2 g t^2

Then, knowing the time in air, the horizontal distance is

d=vhorizontal*time

Answer 2

Thanks!! Could you explain this one to me?

object is projected with a horizontal velocity of 30 m/s. if it hits the ground 5 seconds later, calculate:
The height from which the particle was projected.

Answer 3

h=1/2 g t^2
memorize that equation.

calculate height.

Answer 4

thanks!