a ball is thrown upwards from a tower standing 300 feet tall. the initial velocity of the ball is 32 feet/second. the negative acceleration of the ball due to gravity is -16 in terms of feet per second squared. What is the velocity of the ball after 1 second?

Answer 1

h = -16t^2 + 32t + 300 , from your data
v = dh/dt
= -32t + 32
so when t = 1
v = -32 + 32 = 0