A ball is thrown vertically upwards from a height of 6 ft with an initial velocity of 60 ft per second. How high will the ball go? Note that the acceleration of the ball is given by a(t)= 32 feet per second per second.

Answer 1

h(t) = 6+60t-16t^2
max height at t = -60/-32 = 15/8
h(15/8) = 62.25 ft