A ball is thrown upward from the ground with an initial speed of 25 m/s; at the same instant, a ball is dropped from rest from a building 15 m high. After how long will the balls be at the same height?

Answer 1

X1 = 25 t - 4.9 t^2
X2 = 15 - 4.9 t^2

Set X1 = X2 and solve for t.

25t = 15
t = 3/5 seconds

Answer 2

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