A ball is thrown into the air with an upward velocity of 48 /. Its height ℎ in feet after seconds is given by the function ℎ = −162 + 48 + 9. How long does it take the ball to reach is the maximum height? What is the ball’s maximum height? Round to the nearest hundredth, if necessary.

Question

please help

henry2, · Accepted Answer

V = Vo + g*T = 0 48 + (-32)T = 0 T = 1.5 s.

oobleck · Answer

You need to proofread your post. Clearly you meant h = −16t^2 + 48t + 9 it reaches its maximum height when v=0 v = 48-32t Now you have t, so plug it in to find h

𝓜𝓘𝓐 · Answer

thank you so much

ok · Answer

its 4