To find the height of the ball at t = 3 seconds, substitute t = 3 into the equation:
h = -16t^2 + 60t + 6
h = -16(3)^2 + 60(3) + 6
h = -16(9) + 180 + 6
h = -144 + 180 + 6
h = 42
Therefore, the height of the ball at t = 3 seconds is 42 feet.
Answer: C. 42
a ball is thrown into the air with an initial upward velocity of 60 ft/s. its height (h) in feet after t seconds is given by the function h = -16t^2 + 60t + 6. What will the height be at t = 3 seconds?
(1 point)
A. 35
B. 40
C. 42
D. 45
1 answer