To find when the ball hits the ground, we need to find the time when the height is 0. We can set the equation equal to 0 and solve for t:
-16t^2 + 46t + 6 = 0
We can simplify this equation by dividing all the terms by -2:
8t^2 - 23t - 3 = 0
Now, we can solve this quadratic equation by factoring or using the quadratic formula. Alternatively, we can plug in the values of t in the answer choices and see if any make the equation equal to 0.
Let's plug in t = 3:
8(3)^2 - 23(3) - 3 = 72 - 69 - 3 = 0
Therefore, the ball hits the ground after 3 seconds.
The answer is:
A. 3
a ball is thrown into the air with an initial upward velocity of 46 ft/s. its height (h) in feet after t seconds is given by the function h = -16t^2 + 46t + 6. After how many seconds will the ball hit the ground?
(1 point)
A. 3
B. 4
C. 5
D. 6
1 answer