like this one:
http://www.jiskha.com/display.cgi?id=1224543292
a ball is thrown horizontally -> from the roof of a building 45.0 meters tall and lands 24.0 meters from the base. what was the balls initial speed?
OTHER QUESTION
a shotputter throws the shot with an initial speed of 15.5 m/s @ 34 degrees. calculate the horizontal distance thraveled by the shot if it leaves the hand at a height of 2.20 meters above the ground.
3 answers
shot putter
initial vertical velocity Vo = 15.5 sin 34 = 8.67
initial and always horizontal velocity U = 15.5 cos 34 = 12.9
initial z = 2.2
final z = 0
acceleration = -9.8
so
0 = 2.2 + 8.67 t -4.9 t^2
t = 2 seconds
in 2 seconds it goes 12.9*2 = 25.8
initial vertical velocity Vo = 15.5 sin 34 = 8.67
initial and always horizontal velocity U = 15.5 cos 34 = 12.9
initial z = 2.2
final z = 0
acceleration = -9.8
so
0 = 2.2 + 8.67 t -4.9 t^2
t = 2 seconds
in 2 seconds it goes 12.9*2 = 25.8
not exactly. I'm trying to find the iitial velocity, while in the other problem it is given.
5 answers