This is calculus?
height= vo*time-32*t^2
dheight/dt= vo-64t
t= 96/64 seconds.
max height then is the height(96/64). Calculate.
A ball is thrown directly upward from ground level with an initial velocity v(0) = 96 ft=s.
Assuming that the ball’s only acceleration is that due to gravity (i.e., a(t) = ��32 ft=s2),
determine the maximum height reached by the ball and the time it takes to return to ground
level.
1 answer
1 answer