You can use the range equation to figure this out, first, if the ball even makes it to 100m.
horizontal distance=R=Vi^2*Sin2(Theta)/g
Where
Vi=22m/s
Theta=45
and
g=9.8m/s^2
Solve for R:
R=(22m/s)^2*Sin2(45)/(9.8m/s^2)
R=(22m/s)^2*Sin2(45)/(9.8m/s^2)
R=49.39m
The ball doesn't make it that far.
A ball is thrown at 22 m/s at 45 degrees to the horizontal. A 5 foot tall fence is located 100 meters away. Does
the ball make it over the fence?
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