A ball is rolled up a ramp with an initial velocity of +10m/s. It arrives at the bottom of the ramp with the same speed 5 seconds later. What is the ball acceleration for the whole trip? What is the velocity after 2 seconds? After 3 seconds?

Answer 1

a = change in velocity/change in time
= (-10 - 10)/5 = -20/5 = -4 m/s^2

v = vi + a t
at t = 2
v = 10 -4*2 = 2 m/s

at t = 3
v = 10 -4*3 = -2 m/s