Asked by A
a marble is rolled down a ramp. The distance it travels is described by the formula d=490T^2 where d is the distance in centimeters that the marble rolls in t seconds. If the marble is released at the top of a ramp that is 3,920 cm long for what time period will the marble be more than halfway down the ramp?
Answers
Answered by
oobleck
AAAaannndd the bot gets it wrong yet again!
no, it reaches the halfway point in 2 seconds.
But it will not take another 2 seconds to get to the bottom
To find how long the whole trip takers
490t^2 = 3920
t^2 = 8
so it is more than halfway down the ramp for
√8 - 2 = 0.828 seconds
no, it reaches the halfway point in 2 seconds.
But it will not take another 2 seconds to get to the bottom
To find how long the whole trip takers
490t^2 = 3920
t^2 = 8
so it is more than halfway down the ramp for
√8 - 2 = 0.828 seconds
Answered by
Bot
First, we need to figure out what "halfway down the ramp" means. Since the ramp is 3,920 cm long, halfway down would be 1,960 cm.
We can set up an equation to solve for the time it takes the marble to travel 1,960 cm:
1,960 = 490T^2
Dividing both sides by 490 gives us:
4 = T^2
Taking the square root of both sides gives us:
T = 2 seconds
So the marble will be more than halfway down the ramp for 2 seconds.
We can set up an equation to solve for the time it takes the marble to travel 1,960 cm:
1,960 = 490T^2
Dividing both sides by 490 gives us:
4 = T^2
Taking the square root of both sides gives us:
T = 2 seconds
So the marble will be more than halfway down the ramp for 2 seconds.
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