Xo = 21 m/s.
Yo = 16 m/s.
a. V = Vo = Sqrt(Xo^2 + Yo^2).
b. Y = Yo + g*Tr = 0.
16 - 9.8*Tr = 0.
9.8Tr = 16.
Tr = 1.63 s. = Rise time.
Tf = Tr = 1.63 s.
Tr+Tf = 1.63 + 1.63 = 3.26 s. = Time in air.
c. h = 0.5g*Tf^2 = 4.9*1.63^2 = 13 m.
A ball is kicked with an initial velocity of 21 m/s in the horizontal direction and 16 m/s in the vertical direction. (Assume the ball is kicked from the ground.)
(a) At what speed does the ball hit the ground?
(b) For how long does the ball remain in the air?
(c) What maximum height is attained by the ball?
HELP !
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