a ball is dropped on the ground.The time interval between the 1st and 2nd bounce is 1.2s.The interval between the 1st and 2nd and 3rd bounce is 0.9s.Assume that successive time intevals form a geometric progression with an infinite number of terms.Hence find the total time for which the ball bounces

Question

Reiny · Accepted Answer

So we are to assume that the common ratio is .9/1.2 sec or 3/4 second our total time = 1.2 + 1.2(3/4) + 1.2(3/4)^2 + ... sum(all terms) = a/(1-r) = 1.2/(1-3/4) = 1.2/(1/4) = 4.8 seconds

Akanimoh · Answer

I think the answer is correct

Sssssed · Answer

I u sure is correct

Joshua · Answer

What if , we say,I don't know,I think what we're asked is to find the sum to infinity of the time,which rep the terms as main :ar=1.2 ,ar²=0.9, solving it, we get r=0.75 and a=1.6,we solve with S, and get 6.4 ,how about that ?