A ball is dropped from a height of 1.45m and rebounds to a height of 1.21m. Approximately how many rebounds will the ball make before losing 92% of its energy?
3 answers
Approximatley three
1 - .92 = .08 left
PE = m g h
PE2/PE1 = 1.21/1.45 = .8345
.8345^n = .08
n log .8345 = log .08
n = 13.96 or about 14
PE = m g h
PE2/PE1 = 1.21/1.45 = .8345
.8345^n = .08
n log .8345 = log .08
n = 13.96 or about 14
Just do it
4 answers