A ball is dropped from a height h without air resistance. If the ball falls a distance of h/2 in a time t, how much time is required to fall the remaining h/2?

Question

Could you show steps because I don't understand how to work the problem. Thank you.

Answer 1

starting from rest ... d = 1/2 a t^2
... t = √(2d / a)

doubling the distance ... 2d = 1/2 a T^2
... T = √(4d / a) = t √2

2nd "half" fall time is ... t (√2 - 1)