No second ball has the same acceleration (acceleration of Earths gravity) but it (ball) has initial velocity. It is calculable knowing that in moment of overtaking both balls had the same traveled distance.
g*t^2/2= V*t + g(t-2)^2/2
(t-2) is because the second ball began traveling 2 second after the first
9.81*6^2/2 =v*4 + 9.81*4^2/2
v=24.525m/s (initial velocity of second ball was 24.525m/s)
A ball is dropped from a building, after 2 sec another ball is thrown downward. After 6 sec the second ball overtook the first ball. Is the second ball has greater acceleration than the first ball? Explain.
1 answer
1 answer