Vo = 0
a = 4.5 m/s^2
t = 7.9 s.
d = ?
V = Vo + a*t = 0 + 4.5*7.9 = 35.6 m/s.
V^2 = Vo^2 + 2a*d = 35.6^2
Vo^2 + 2a*d = 35.6^2. Solve for d.
A ball initially at rest rolls down a hill with
an acceleration of 4.5 m/s2.
If it accelerates for 7.9 s, how far will it
move?
Answer in units of m
1 answer