A ball initially at rest rolls down a hill with

Question

an acceleration of 4.5 m/s2.
If it accelerates for 7.9 s, how far will it
move?
Answer in units of m

Answer 1

Vo = 0
a = 4.5 m/s^2
t = 7.9 s.
d = ?

V = Vo + a*t = 0 + 4.5*7.9 = 35.6 m/s.

V^2 = Vo^2 + 2a*d = 35.6^2
Vo^2 + 2a*d = 35.6^2. Solve for d.