A 28 kg ball initially at rest rolls down a 159 m hill. When the ball reaches the bottom it is traveling at 31.3 m/s.

How much energy is dissipated by friction on the ball?

1 answer

PE = mgh = 28*9.8*159
KE = 1/2 mv^2 = 1/2 * 28 * 31.3^2

Because of friction, not all of the PE changed to KE. Subtract to see how much energy was lost.