PE = mgh = 28*9.8*159
KE = 1/2 mv^2 = 1/2 * 28 * 31.3^2
Because of friction, not all of the PE changed to KE. Subtract to see how much energy was lost.
A 28 kg ball initially at rest rolls down a 159 m hill. When the ball reaches the bottom it is traveling at 31.3 m/s.
How much energy is dissipated by friction on the ball?
1 answer