X = (1/2) a t^2
t is the time spent falling, and a is the acceleration. Solve for a using X = 45 m and t = 3.0 s.
a = 2X/t^2 = 90 m/9s^2 = 10 m/s^2
A ball falling from rest is located 45 m below its starting point 3.0 s later. Assuming that its acceleration is uniform, what is its value?
1 answer
1 answer