two problems here:
1. velocity is not in m/s^2
2. It should bounce back with an upward (positive) velocity.
A ball dropped from a sixth floor window accelerates at 10m/s squared. After 2 seconds it hits the ground. It bounces back with a velocity of -15m/s squared.
A. What is the balls velocity when it hits the ground?
b. The ball is in contact with the ground for 0.02 s when it bounces. What is its mean acceleration while it is in contact with the ground?
4 answers
sorry
A ball dropped from a sixth floor window accelerates at 10m/s squared. After 2 seconds it hits the ground. It bounces back with a velocity of -15m/s.
A ball dropped from a sixth floor window accelerates at 10m/s squared. After 2 seconds it hits the ground. It bounces back with a velocity of -15m/s.
this is what the worksheet says, that is why im soo confused
see the problem
http://www.jiskha.com/display.cgi?id=1380223491
Steve said it should bounce back at 15, but that presumes upward as + direction. One can make it the - direction, but that is seldom done. The direction signs are arbritary.
http://www.jiskha.com/display.cgi?id=1380223491
Steve said it should bounce back at 15, but that presumes upward as + direction. One can make it the - direction, but that is seldom done. The direction signs are arbritary.