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A bacteria has a growth rate constant of 0.02. If initially, the number of bacteria is 1000, what is the time before it reaches a population of 100,000?

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So, you have P(t) = 1000 e^(.02t)
so solve
1000 e^(.02t) = 100,000
e^(.02t) = 100
.02t = ln100
t = ln100/.02 = 230.26

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