a, b, c, d and e are distinct integers such that (5−a)(5−b)(5−c)(5−d)(5−e)=28. What is the value of a+b+c+d+e?

Answer 1

well, since the only factors of 28 are ±1,±2,±4,±7 I'd have to go with
(2)(-2)(1)(-1)(7)
(5-3)(5-7)(5-4)(5-6)(5-(-2)) = 28
3+7+4+6-2 = 18

Answer 2

thanks...