1/a + 1/b = 1/16
1/b + 1/c = 1/32
4/a + 12/b + 48/c = 1
a can do the job in 160/7 days
b can do the job in 160/3 days
c can do the job in 80 days.
Check:
a can do 7/160 jobs in 1 day, and 28/160 jobs in 4 days
b can do 3/160 jobs in 1 day, and 36/160 jobs in 12 days
c can do 1/80 job in 1 day, and 48/80 jobs in 48 days
7/160 + 3/160 = 10/160 = 1/16 so a&b take 16 days
3/160+1/80 = 5/160 = 1/32 so b&c take 32 days
28/160 + 36/160 + 48/80 = 1, as expected.
a and b together can do a piece of work in16 days.b and c can do same work in 32 days.after a worked for 4 days and b for 12 days c takes it up and finishes it in 48 days.in how many days will each of them complete work
1 answer
1 answer