(a)(12 - 10) / 12 = (1/2)^(t / 5700)
log(1/6) = (t / 5700) log(1/2)
(b) (10 - c) / 10 = (1/2)^(150 / 5700)
(a)-A fossilised tree was tested and contains 10 grams of Carbon-14. Given that there was 12 grams of Carbon-14 present when it died, determine the age of the fossil? Half life of Carbon-14 is 5700 years.
(b)How much Carbon-14 will be present in the sample 150 years from now?
1 answer
1 answer