a) 10/12 = (1/2)^(t/5700)
[log(10/12)] / log(1/2) = t / 5700
b) use t from a)
c = 12 * (1/2)^[(t+100)/5700]
c / 12 = (1/2)^[(t+100)/5700]
(a)-A fossilised tree was tested and contains 10 grams of Carbon-14. Given that there was 12 grams of Carbon-14 present when it died, determine the age of the fossil? Half life of Carbon-14 is 5700 years.
(b)How much Carbon-14 will be present in the sample 100 years from now?
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