A 8.0×10−2 kg arrow hits the target at 25 m/s and penetrates 3.8 cm before stopping.

Question

What average force did the target exert on the arrow?
What average force did the arrow exert on the target?

Answer 1

a.
average force did the target exert on the arrow
Work done = force * distance = energy lost
Initial kinetic energy = (1/2)mv²
work done = F*d
Equating energy lost to work done
F*d = (1/2)mv²
F=d*mv*sup2;/2

b) What do you know about Newton's third law?

Answer 2

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