Mass m = 77 g = 0.077 kg
Force F = 125 N
Distance s = 81 cm = 0.81 m
Speed V = ?
We know that
Work done on the arrow = F *s
=>1/2*m*V^2 =F*s
=>V = √((2*F*s)/m) = √((2*125*0.81)/(.077)) = 51.28 m/s
A 77 g arrow is fired from a bow whose string exerts an average force of 95 N on the arrow over a distance of 81 cm. What is the speed of the arrow as it leaves the bow?
1 answer