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nammilee_2012

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The electric field between the plates of a paper-separated capacitor is 8.18×104 . The plates are 2.20 apart, and the charge on
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A radioactive nucleus at rest decays into a second nucleus, anelectron, and a neutrino. The electron and neutrino are emitted
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A 0.500 kg ice puck, moving east with a speed of 3.30 m/s, has a head-on collision with a 0.900 kg puck initially at rest.
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Suppose, The velocity of .5 kg ice puck before collision = u1= 3.30 m/s The velocity of .9 kg ice puck before collision = u2= 0 The velocity of .5 kg ice puck after collision = v1=? The velocity of .9 kg ice puck after collision = v2=? According to
A 0.500 kg ice puck, moving east with a speed of 3.30 m/s, has a head-on collision with a 0.900 kg puck initially at rest. Assuming a perfectly elastic collision, (a) what will be the speed of the 0.500 kg object after the collision? (b) What will be the
Mass m = 77 g = 0.077 kg Force F = 125 N Distance s = 81 cm = 0.81 m Speed V = ? We know that Work done on the arrow = F *s =>1/2*m*V^2 =F*s =>V = √((2*F*s)/m) = √((2*125*0.81)/(.077)) = 51.28 m/s

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