h = 1.3*sin30 = 0.65 m.
Vo = 50cm = 0.50 m.
V = Speed at bottom of the ramp.
V^2 = Vo^2 + 2g*h.
V^2 = 0.50^2 + 19.8*0.65 =
V = 3.60 m/s.
A 751 kg block is pushed on the slope of a 30◦
frictionless inclined plane to give it an initial
speed of 50 cm/s along the slope when the
block is 1.3 m from the bottom of the incline.
The acceleration of gravity is 9.8 m/s^2. What is the speed of the block at the bottom for the plane?
1 answer