A 72 kg man drops to a concrete patio from a window only 0.60 m above the patio. He neglects to bend his knees on landing, taking 2.0 cm to stop.

(a) What is his average acceleration from when his feet first touch the patio to when he stops?
m/s2

(b) What is the magnitude of the average stopping force?
kN

1 answer

vf^2=vi^2+2ad solve for a.
force=mass*a