The approach is correct...and the answer is correct for a one storey building.
Replace (3+0.5) by (3*3+1)
3 storeys+1m above floor.
A 7 kilogram bowling ball is dropped from a fourth story window. If each story is 3 meters high, use energy conservation (not the equations of motion) to find the ball's velocity when it strikes the ground. Ignore air resistance.
1/2 m v^2= mgh
v= sqrt (2g*(3+.5))
V=sqrt(2)(9.8)(3)
v=sqrt58.8
v=7.67 m/s
did I do this right? thanks
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