A 7 kilogram bowling ball is dropped from a fourth story window. If each story is 3 meters high, use energy conservation (not the equations of motion) to find the ball's velocity when it strikes the ground. Ignore air resistance.
1/2 m v^2= mgh
v= sqrt (2g*(3+.5))
V=sqrt(2)(9.8)(3)
v=sqrt58.8
v=7.67 m/s
did I do this right? thanks
0 answers