A 6kg mass is resting on a horizontal surface. it is determined that a force of 20N will start the object sliding and keep it sliding with an acceleration of 0.83. what are the coefficient of static friction and kinetic friction between the mass and the surface?
4 answers
I need the answer now
First the static friction
F = mu m g
20 = mu * 6 * 9.81 (on earth)
mu = 20 / (6*9.81) = 0.34 static
then sliding
F - mu m g = m a
20 - mu (6*9.81) = 6 *0.83
58.9 mu = 20 - 4.98 = 15
mu = 0.25 kinetic
F = mu m g
20 = mu * 6 * 9.81 (on earth)
mu = 20 / (6*9.81) = 0.34 static
then sliding
F - mu m g = m a
20 - mu (6*9.81) = 6 *0.83
58.9 mu = 20 - 4.98 = 15
mu = 0.25 kinetic
Sorry to be so slow about the reply. I retired long before you were born I suspect (was a student at Punahoe school when Pearl Harbor was bombed) and have trouble keeping up.
Really appreciate to the answer thank u guys help a lot
1 answer