A 66.0 kg rider sitting on a 7.1 kg bike is riding along at 9.4 m/s in the positive direction. The rider drags a foot on the ground and slows down to 6.5 m/s still in the positive direction. What is the change in momentum of the rider and bike?
1 answer
Δp=(m1+m2)Δν=(66+7.1)(9.4-6.5)=202 kg•m/s
1 answer