to get the largest speed, you need the largest accelerating force.
The force pulling up reduces weight, thus friction. So there is an optimum angle.
Net force=m*a
125CosTheta-(mg*mu(1-sinTheta))=ma
so you want to maximize a. Take the derivative of each side with respect to theta.
-125SinTheta-(mg*mu)(-cosTheta)=0
TanTheta=mg*mu/125
check all that.
A 6.53-kg block initially at rest is pulled to the right along a horizontal surface by a
constant force of 125 N applied at an angle θ above the horizontal. The coefficient of
kinetic friction between the block and the horizontal surface is 0.150. At what angle θ
above the horizontal surface should the force be applied to achieve the largest possible
speed after the block has moved 5.00 m to the right?
3 answers
Pay the 20 dollars or use the book to solve it.
Get back to school and ask your Teacher to teach u back!?
1 answer