weight = mg = 4.1 * 9.8 = 40.2 Newtons
Horizontal friction = 0.103 * 40.2 = 4.14 Newtons
net horizontal force = 12.6 - 4.14 = 8.46 N
a = F/m = 8.46 / 4.1 = 2.06 m/s^2
v = a t
x = (1/2) a t^2
2.12 = 1.03 t^2
t = 1.435 seconds
v = 2.06 m/s^2 * 1.435 s = 2.96 m/s
A 4.1 kg block initially at rest is pulled to the right along a horizontal surface by a constant, horizontal force of 12.6 N. The coefficient of kinetic friction is 0.103.
The acceleration of gravity is 9.8 m/s^2.
Find the speed of the block after it has moved 2.12 m.
Answer in units of m/s.
1 answer