mu(m1+m2)g = (m1+m2)a
so mu(g) = a
speed before slide begins:
v = sqrt(2ax)
m1 vi = (m1+m2)v
solve for vi
A 6.00g bullet is fired horizontally into a 1.50kg wooden block resting on a horizontal surface. The coefficient of kinetic friction between block and surface is .30. the bullet remains embedded in the block, which is oserved to slide .25m along the surface before stopping. what was the initial speed of the bullet
1 answer
1 answer