A 12.0 g bullet is fired horizontally into a 108 g wooden block that is initially at rest on a frictionless horizontal surface and connected to a spring of constant 144 N/m. The bullet becomes embedded in the block. If the bullet-block system compresses the spring by a maximum of 82.0 cm, what was the speed of the bullet at impact with the block?
What equation would I have use to solve the question??
4 answers
What is the stored energy in the spring at max compression? What Veloicity does that equal on the block/bullet system. Waht momentum is that? Then, finally that momentum is the mometnum of the bullet...solve for bullet speed.
I am so cunfused? Can you still use the PEi+PEs+KE = PEf+PEs+KE?
No. You cant use that. conservation of energy does not apply when the bullet hits the block.
You can use conservation of energy at
spring: block, but that is all.
You can use conservation of energy at
spring: block, but that is all.
Then how would I set it up?
0 answers