energy in spring=1/2 kx^2 compute that.
Intiial velocity of block/bullet combo:
= 1/2 (M+m)V=energy in spring, solve for V
Now, using the conservation of momentum
momentumbullet=momentum(block+bullet)
mVb=(m+M)V solve for Vb
A 11.0-g bullet is fired horizontally into a 101-g wooden block that is initially at rest on a frictionless horizontal surface and connected to a spring having spring constant 160 N/m. The bullet becomes embedded in the block. If the bullet-block system compresses the spring by a maximum of 76.0 cm, what was the speed of the bullet at impact with the block?
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