a 5kg box is pulled along the floor by a rope that makes a 25 degree angle with the horizontal. the coefficient of kinetic friction between the box and the floor is 0.25. If the box accelerates at a rate of 1.5 m/s squared, what must be the tension of the rope?

Answer 1

two things you have to do.
friction force=mu*(mg-Tension*sin25)

pulling force-frictionforce=m*a
Tension-mu(mg-Tension*sin25)=mg
solve for tension